What is 2i\times (-2)i ?

The solution to 2i\times (-2)i is 4

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simplify 2i\times (-2)i

simplify

2 i \cdot (- 2) i

4

Solution steps

2 i (- 2) i

Multiply the numbers:

2 (- 2) = - 4

= - 4 ii

Apply exponent rule:

aa = a^{2}

ii = i^{2}

= - 4 i^{2}

Apply imaginary number rule:

i^{2} = - 1

= - 4 (- 1)

Multiply the numbers:

- 4 (- 1) = 4

= 4

(- i 2)^{2}

\frac{1}{5} \times (- 2)

\frac{2}{5 6}

H C L + N a^{2} C O^{3}

\frac{2 x ^{2} + 7 x + 6}{x ^{2} - x - 6}