What is factor 16-8x+x^2 ?

The solution to factor 16-8x+x^2 is (x-4)^2

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factor 16-8x+x^2

factor

16 - 8 x + x^{2}

(x - 4)^{2}

Solution steps

16 - 8 x + x^{2}

Write in the standard form

= x^{2} - 8 x + 16

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 = 4^{2}

- 8 x = - 2 x \cdot 4

= x^{2} - 2 x \cdot 4 + 4^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

x^{2} - 2 x \cdot 4 + 4^{2} = (x - 4)^{2}

= (x - 4)^{2}

1 - - 5 + 9 - - 5

x^{2} + \frac{5}{2} x + 1

(x^{2} + 6) (x^{2} + 2)

2 1 \frac{9}{16} - 1

- 2 \frac{\frac{4}{5}}{( - 7 )}