What are the solutions to the equation 12x^2-7x+1=0 ?

The solutions to the equation 12x^2-7x+1=0 are x= 1/3 ,x= 1/4

Find the zeros of 12x^2-7x+1=0

The zeros of 12x^2-7x+1=0 are x= 1/3 ,x= 1/4

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12 x^{2} - 7 x + 1 = 0

x = \frac{1}{3}, x = \frac{1}{4}

Solution steps

12 x^{2} - 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 12 \cdot 1}{2 \cdot 12}

(- 7)^{2} - 4 \cdot 12 \cdot 1 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 12}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 12}

x = \frac{- ( - 7 ) + 1}{2 \cdot 12} : \frac{1}{3}

x = \frac{- ( - 7 ) - 1}{2 \cdot 12} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = \frac{1}{4}

(x + 1)^{- \frac{1}{2}}

4 x + 8 < 128

4 (x + 7)^{2} = 11

2 x^{2} - 6 x + 10 = 0

0 < 2 x - 2 \leq 8

What are the solutions to the equation 12x^2-7x+1=0 ?
The solutions to the equation 12x^2-7x+1=0 are x= 1/3 ,x= 1/4
Find the zeros of 12x^2-7x+1=0
The zeros of 12x^2-7x+1=0 are x= 1/3 ,x= 1/4