What is expand (x+3)(2x^2+4x-4) ?

The solution to expand (x+3)(2x^2+4x-4) is 2x^3+10x^2+8x-12

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expand (x+3)(2x^2+4x-4)

expand

(x + 3) (2 x^{2} + 4 x - 4)

2 x^{3} + 10 x^{2} + 8 x - 12

Solution steps

(x + 3) (2 x^{2} + 4 x - 4)

Distribute parentheses

= x \cdot 2 x^{2} + x \cdot 4 x + x (- 4) + 3 \cdot 2 x^{2} + 3 \cdot 4 x + 3 (- 4)

Simplify

x \cdot 2 x^{2} + x \cdot 4 x + x (- 4) + 3 \cdot 2 x^{2} + 3 \cdot 4 x + 3 (- 4) : 2 x^{3} + 10 x^{2} + 8 x - 12

= 2 x^{3} + 10 x^{2} + 8 x - 12

\frac{( x ^{2} - 2 x )}{( - 3 x ^{2} + 9 x - 6 )}

\frac{10}{50}

16 - 2 (4 + 3 x)

(- 2 x + 4) - (- x - 5)

2 \times 32

What is expand (x+3)(2x^2+4x-4) ?
The solution to expand (x+3)(2x^2+4x-4) is 2x^3+10x^2+8x-12