What are the solutions to the equation 5u^2-4u=0 ?

The solutions to the equation 5u^2-4u=0 are u= 4/5 ,u=0

Find the zeros of 5u^2-4u=0

The zeros of 5u^2-4u=0 are u= 4/5 ,u=0

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5 u^{2} - 4 u = 0

u = \frac{4}{5}, u = 0

Solution steps

5 u^{2} - 4 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 \cdot 0 = 4

u_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 5}

Separate the solutions

u_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 5}, u_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 5}

u = \frac{- ( - 4 ) + 4}{2 \cdot 5} : \frac{4}{5}

u = \frac{- ( - 4 ) - 4}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

u = \frac{4}{5}, u = 0

4 x - 7 \geq 9

(2 s + 1) - 3 \leq - 8

(x + 2) (x - 1) = 0

\frac{2 π}{30}

5 - x^{2} < - 2

What are the solutions to the equation 5u^2-4u=0 ?
The solutions to the equation 5u^2-4u=0 are u= 4/5 ,u=0
Find the zeros of 5u^2-4u=0
The zeros of 5u^2-4u=0 are u= 4/5 ,u=0