What is (x^2+3x-28)/(x^2-7x+12) ?

The solution to (x^2+3x-28)/(x^2-7x+12) is (x+7)/(x-3)

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simplify (x^2+3x-28)/(x^2-7x+12)

simplify

\frac{x ^{2} + 3 x - 28}{x ^{2} - 7 x + 12}

\frac{x + 7}{x - 3}

Solution steps

\frac{x ^{2} + 3 x - 28}{x ^{2} - 7 x + 12}

Factor

x^{2} + 3 x - 28 : (x - 4) (x + 7)

= \frac{( x - 4 ) ( x + 7 )}{x ^{2} - 7 x + 12}

Factor

x^{2} - 7 x + 12 : (x - 3) (x - 4)

= \frac{( x - 4 ) ( x + 7 )}{( x - 3 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{x + 7}{x - 3}

(5 - 8 i) - 2 i (2 - 3 i)

(2 x + 7) (x - 7)

- 5 i \cdot 5 i

- 2 (- \frac{x}{2})

What is (x^2+3x-28)/(x^2-7x+12) ?
The solution to (x^2+3x-28)/(x^2-7x+12) is (x+7)/(x-3)