What is factor 1b^2+8b+12 ?

The solution to factor 1b^2+8b+12 is (b+2)(b+6)

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factor 1b^2+8b+12

factor

1 b^{2} + 8 b + 12

(b + 2) (b + 6)

Solution steps

1 \cdot b^{2} + 8 b + 12

Break the expression into groups

= (b^{2} + 2 b) + (6 b + 12)

Factor out

b

from

b^{2} + 2 b : b (b + 2)

Factor out

6

from

6 b + 12 : 6 (b + 2)

= b (b + 2) + 6 (b + 2)

Factor out common term

b + 2

= (b + 2) (b + 6)

1^{2} + b^{2} = 3^{2}

n^{2} - 3 n = - 7

- 2 x^{2} + x + 1

- x = 1

\frac{x}{9} = 81