What is (4x^2-16x+12)/(x^2-9) ?

The solution to (4x^2-16x+12)/(x^2-9) is (4(x-1))/(x+3)

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simplify (4x^2-16x+12)/(x^2-9)

simplify

\frac{4 x ^{2} - 16 x + 12}{x ^{2} - 9}

\frac{4 ( x - 1 )}{x + 3}

Solution steps

\frac{4 x ^{2} - 16 x + 12}{x ^{2} - 9}

Factor

4 x^{2} - 16 x + 12 : 4 (x - 1) (x - 3)

= \frac{4 ( x - 1 ) ( x - 3 )}{x ^{2} - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{4 ( x - 1 ) ( x - 3 )}{( x + 3 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{4 ( x - 1 )}{x + 3}

964

2^{3} \times 2^{3}

\frac{3}{10} \div \frac{2}{5}

\frac{9}{5} \times \frac{2}{3}

\frac{4}{3} \times \frac{1}{2}

What is (4x^2-16x+12)/(x^2-9) ?
The solution to (4x^2-16x+12)/(x^2-9) is (4(x-1))/(x+3)