What are the solutions to the equation (2-4d)(2+4d)=0 ?

The solutions to the equation (2-4d)(2+4d)=0 are d= 1/2 ,d=-1/2

Find the zeros of (2-4d)(2+4d)=0

The zeros of (2-4d)(2+4d)=0 are d= 1/2 ,d=-1/2

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(2 - 4 d) (2 + 4 d) = 0

d = \frac{1}{2}, d = - \frac{1}{2}

Decimal Notation

d = 0.5, d = - 0.5

Solution steps

(2 - 4 d) (2 + 4 d) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 - 4 d = 0 or 2 + 4 d = 0

Solve

2 - 4 d = 0 : d = \frac{1}{2}

Solve

2 + 4 d = 0 : d = - \frac{1}{2}

The solutions to the quadratic equation are:

d = \frac{1}{2}, d = - \frac{1}{2}

- 5 x - 4 > 21

6 \times 3

r^{2} + r - 90

- \frac{18}{4}

((\frac{1}{2})^{3})^{5}

What are the solutions to the equation (2-4d)(2+4d)=0 ?
The solutions to the equation (2-4d)(2+4d)=0 are d= 1/2 ,d=-1/2
Find the zeros of (2-4d)(2+4d)=0
The zeros of (2-4d)(2+4d)=0 are d= 1/2 ,d=-1/2