What is -2 1/5 \div (-3)/7 ?

The solution to -2 1/5 \div (-3)/7 is 5 2/15

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-2 1/5 \div (-3)/7

- 2 \frac{1}{5} \div \frac{- 3}{7}

5 \frac{2}{15}

Solution steps

- 2 \frac{1}{5} \div \frac{- 3}{7}

Convert mixed numbers to improper fractions:

2 \frac{1}{5} = \frac{11}{5}

= - \frac{11}{5} \div \frac{- 3}{7}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= - \frac{11}{5} \times \frac{7}{- 3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{11}{5} (- \frac{7}{3})

Apply rule

- (- a) = a

= \frac{11}{5} \times \frac{7}{3}

Multiply fractions:

\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}

= \frac{11 \times 7}{5 \times 3}

Multiply the numbers:

11 \times 7 = 77

= \frac{77}{5 \times 3}

Multiply the numbers:

5 \times 3 = 15

= \frac{77}{15}

Convert improper fractions to mixed numbers:

\frac{77}{15} = 5 \frac{2}{15}

= 5 \frac{2}{15}

\frac{7 x}{x ^{2} + 6 x + 9} + \frac{1}{x ^{2} - 9}

(- 1 + 4 i) (9 - 4 i)

50 \times 3

23 \cdot 223

(x + n)^{2}