What is 1/(sqrt(2x^2-7x+6)) ?

The solution to 1/(sqrt(2x^2-7x+6)) is (sqrt(2x^2-7x+6))/(2x^2-7x+6)

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simplify 1/(sqrt(2x^2-7x+6))

simplify

\frac{1}{2 x ^{2} - 7 x + 6}

\frac{2 x ^{2} - 7 x + 6}{2 x ^{2} - 7 x + 6}

Solution steps

\frac{1}{2 x ^{2} - 7 x + 6}

Multiply by the conjugate

\frac{2 x ^{2} - 7 x + 6}{2 x ^{2} - 7 x + 6}

= \frac{1 \cdot 2 x ^{2} - 7 x + 6}{2 x ^{2} - 7 x + 6 2 x ^{2} - 7 x + 6}

1 \cdot 2 x^{2} - 7 x + 6 = 2 x^{2} - 7 x + 6

2 x^{2} - 7 x + 6 2 x^{2} - 7 x + 6 = 2 x^{2} - 7 x + 6

= \frac{2 x ^{2} - 7 x + 6}{2 x ^{2} - 7 x + 6}

lo g_{15} (3375)

\frac{1}{5} \div \frac{15}{4}

\frac{20 x ^{3} y ^{5}}{50 x ^{2} y ^{3}}

x^{2} + 0 x - 144

(3^{3})^{3}

What is 1/(sqrt(2x^2-7x+6)) ?
The solution to 1/(sqrt(2x^2-7x+6)) is (sqrt(2x^2-7x+6))/(2x^2-7x+6)