What are the solutions to the equation j^2-20j+100=0 ?

The solutions to the equation j^2-20j+100=0 are j=10

Find the zeros of j^2-20j+100=0

The zeros of j^2-20j+100=0 are j=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

j^{2} - 20 j + 100 = 0

j = 10

Solution steps

j^{2} - 20 j + 100 = 0

Solve with the quadratic formula

j_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 100 = 0

j_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 1}

j = \frac{- ( - 20 )}{2 \cdot 1}

\frac{- ( - 20 )}{2 \cdot 1} = 10

j = 10

The solution to the quadratic equation is:

j = 10

(3 x + 1) (2 x - 1) - 2 x^{2} = (2 x - 3)^{2} + 6 x + 5

- \frac{7}{9} (x + 3) = 14

16 + 30 i

2 (3 y - 9) \geq 7 (2 y + 5)

- 4 (5 x - 9) \geq - 24

What are the solutions to the equation j^2-20j+100=0 ?
The solutions to the equation j^2-20j+100=0 are j=10
Find the zeros of j^2-20j+100=0
The zeros of j^2-20j+100=0 are j=10