What is factor x^4+x^3+2x^2+4x-8 ?

The solution to factor x^4+x^3+2x^2+4x-8 is (x-1)(x+2)(x^2+4)

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factor x^4+x^3+2x^2+4x-8

factor

x^{4} + x^{3} + 2 x^{2} + 4 x - 8

(x - 1) (x + 2) (x^{2} + 4)

Solution steps

x^{4} + x^{3} + 2 x^{2} + 4 x - 8

Use the rational root theorem

= (x - 1) \frac{x ^{4} + x ^{3} + 2 x ^{2} + 4 x - 8}{x - 1}

\frac{x ^{4} + x ^{3} + 2 x ^{2} + 4 x - 8}{x - 1} = x^{3} + 2 x^{2} + 4 x + 8

= (x - 1) (x^{3} + 2 x^{2} + 4 x + 8)

Factor

x^{3} + 2 x^{2} + 4 x + 8 : (x + 2) (x^{2} + 4)

= (x - 1) (x + 2) (x^{2} + 4)

144 - x^{2}

82 + 0 i

\frac{0.5}{2200 \cdot 1 0 ^{- 6}}

32 \cdot 243

\frac{260}{3}

What is factor x^4+x^3+2x^2+4x-8 ?
The solution to factor x^4+x^3+2x^2+4x-8 is (x-1)(x+2)(x^2+4)