What is 3/(x^2-3x)-4/(x^2-4x+3) ?

The solution to 3/(x^2-3x)-4/(x^2-4x+3) is (-x-3)/(x(x-3)(x-1))

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simplify 3/(x^2-3x)-4/(x^2-4x+3)

simplify

\frac{3}{x ^{2} - 3 x} - \frac{4}{x ^{2} - 4 x + 3}

\frac{- x - 3}{x ( x - 3 ) ( x - 1 )}

Solution steps

\frac{3}{x ^{2} - 3 x} - \frac{4}{x ^{2} - 4 x + 3}

Least Common Multiplier of

x^{2} - 3 x, x^{2} - 4 x + 3 : x (x - 3) (x - 1)

Adjust Fractions based on the LCM

= \frac{3 ( x - 1 )}{x ( x - 3 ) ( x - 1 )} - \frac{4 x}{x ( x - 3 ) ( x - 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{3 ( x - 1 ) - 4 x}{x ( x - 3 ) ( x - 1 )}

Simplify

3 (x - 1) - 4 x : - x - 3

= \frac{- x - 3}{x ( x - 3 ) ( x - 1 )}

(2 x - 2) (2 x + 2)

14 + 3 y^{2} + 30 y - 3 y^{2} - 4 y - 14 - 16 y

30 x^{3} + 15 x^{2} - 18 x - 9

lo g_{2} (300)

\frac{a ^{10}}{a \cdot a ^{2}}

What is 3/(x^2-3x)-4/(x^2-4x+3) ?
The solution to 3/(x^2-3x)-4/(x^2-4x+3) is (-x-3)/(x(x-3)(x-1))