What is factor 4y^2+8y+3 ?

The solution to factor 4y^2+8y+3 is (2y+1)(2y+3)

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factor 4y^2+8y+3

factor

4 y^{2} + 8 y + 3

(2 y + 1) (2 y + 3)

Solution steps

4 y^{2} + 8 y + 3

Break the expression into groups

= (4 y^{2} + 2 y) + (6 y + 3)

Factor out

2 y

from

4 y^{2} + 2 y : 2 y (2 y + 1)

Factor out

3

from

6 y + 3 : 3 (2 y + 1)

= 2 y (2 y + 1) + 3 (2 y + 1)

Factor out common term

2 y + 1

= (2 y + 1) (2 y + 3)

tan (θ) cot (θ)

lo g_{5} (\frac{1}{25})

3 p - 4 q - p - 3 q

- 2 x^{2} - 8 x

- 5 j + (- 2) j + 6 j - 9 - 8 + (- 5) j