What is factor 2x^3-7x^2-19x+60 ?

The solution to factor 2x^3-7x^2-19x+60 is (x+3)(2x-5)(x-4)

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factor 2x^3-7x^2-19x+60

factor

2 x^{3} - 7 x^{2} - 19 x + 60

(x + 3) (2 x - 5) (x - 4)

Solution steps

2 x^{3} - 7 x^{2} - 19 x + 60

Use the rational root theorem

= (x + 3) \frac{2 x ^{3} - 7 x ^{2} - 19 x + 60}{x + 3}

\frac{2 x ^{3} - 7 x ^{2} - 19 x + 60}{x + 3} = 2 x^{2} - 13 x + 20

= (x + 3) (2 x^{2} - 13 x + 20)

Factor

2 x^{2} - 13 x + 20 : (2 x - 5) (x - 4)

= (x + 3) (2 x - 5) (x - 4)

lo g_{12} (4)

x^{4} - 2 x^{3} - 21 x^{2} + 22 x + 40

(x^{2})^{3} + x^{2}

\frac{4 + 6}{2 3}

8 x^{2} + 34 x + 35

What is factor 2x^3-7x^2-19x+60 ?
The solution to factor 2x^3-7x^2-19x+60 is (x+3)(2x-5)(x-4)