What is factor x^4-2x^3-21x^2+22x+40 ?

The solution to factor x^4-2x^3-21x^2+22x+40 is (x+1)(x-2)(x+4)(x-5)

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factor x^4-2x^3-21x^2+22x+40

factor

x^{4} - 2 x^{3} - 21 x^{2} + 22 x + 40

(x + 1) (x - 2) (x + 4) (x - 5)

Solution steps

x^{4} - 2 x^{3} - 21 x^{2} + 22 x + 40

Use the rational root theorem

= (x + 1) \frac{x ^{4} - 2 x ^{3} - 21 x ^{2} + 22 x + 40}{x + 1}

\frac{x ^{4} - 2 x ^{3} - 21 x ^{2} + 22 x + 40}{x + 1} = x^{3} - 3 x^{2} - 18 x + 40

= (x + 1) (x^{3} - 3 x^{2} - 18 x + 40)

Factor

x^{3} - 3 x^{2} - 18 x + 40 : (x - 2) (x + 4) (x - 5)

= (x + 1) (x - 2) (x + 4) (x - 5)

(x^{2})^{3} + x^{2}

\frac{4 + 6}{2 3}

8 x^{2} + 34 x + 35

9 x^{4} + 72 x^{3} + 23 x^{2} - 308 x - 196

\frac{47}{4}

What is factor x^4-2x^3-21x^2+22x+40 ?
The solution to factor x^4-2x^3-21x^2+22x+40 is (x+1)(x-2)(x+4)(x-5)