What are the solutions to the equation 1/2 x^2+5x+1/2 x^2=-6 ?

The solutions to the equation 1/2 x^2+5x+1/2 x^2=-6 are x=-2,x=-3

Find the zeros of 1/2 x^2+5x+1/2 x^2=-6

The zeros of 1/2 x^2+5x+1/2 x^2=-6 are x=-2,x=-3

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\frac{1}{2} x^{2} + 5 x + \frac{1}{2} x^{2} = - 6

x = - 2, x = - 3

Solution steps

\frac{1}{2} x^{2} + 5 x + \frac{1}{2} x^{2} = - 6

Multiply both sides by

2

x^{2} + 10 x + x^{2} = - 12

2 x^{2} + 10 x = - 12

Move

12

to the left side

2 x^{2} + 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 12 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 2}, x_{2} = \frac{- 10 - 2}{2 \cdot 2}

x = \frac{- 10 + 2}{2 \cdot 2} : - 2

x = \frac{- 10 - 2}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

a, y = a e^{\frac{1}{2} (- 2)} + b e^{- \frac{1}{2} (- 2)}

\frac{( 4 - x )}{( - 2 )} \leq 1

m (b - a) - p (a - b)

49 t^{6} - 4 k^{8}

48 = 6 x

What are the solutions to the equation 1/2 x^2+5x+1/2 x^2=-6 ?
The solutions to the equation 1/2 x^2+5x+1/2 x^2=-6 are x=-2,x=-3
Find the zeros of 1/2 x^2+5x+1/2 x^2=-6
The zeros of 1/2 x^2+5x+1/2 x^2=-6 are x=-2,x=-3