What is 1/(4+6i)+1/(2-4i) ?

The solution to 1/(4+6i)+1/(2-4i) is 23/130+11/130 i

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simplify 1/(4+6i)+1/(2-4i)

simplify

\frac{1}{4 + 6 i} + \frac{1}{2 - 4 i}

\frac{23}{130} + \frac{11}{130} i

Solution steps

\frac{1}{4 + 6 i} + \frac{1}{2 - 4 i}

\frac{1}{4 + 6 i} = \frac{2 - 3 i}{26}

\frac{1}{2 - 4 i} = \frac{1 + 2 i}{10}

= \frac{2 - 3 i}{26} + \frac{1 + 2 i}{10}

Join

\frac{2 - 3 i}{26} + \frac{1 + 2 i}{10} : \frac{11 i + 23}{130}

= \frac{11 i + 23}{130}

Rewrite in standard complex form:

\frac{23}{130} + \frac{11}{130} i

= \frac{23}{130} + \frac{11}{130} i

(6 x)^{0}

49 x^{8} - 16 y^{14}

∣ x ∣ \times ∣ x ∣

(x - 1)^{7}

52 \cdot 3

What is 1/(4+6i)+1/(2-4i) ?
The solution to 1/(4+6i)+1/(2-4i) is 23/130+11/130 i