What is (6-3i)+(4-2i) ?

The solution to (6-3i)+(4-2i) is 10-5i

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simplify (6-3i)+(4-2i)

simplify

(6 - 3 i) + (4 - 2 i)

10 - 5 i

Solution steps

(6 - 3 i) + (4 - 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (6 + 4) + (- 3 - 2) i

Simplify

(6 + 4) + (- 3 - 2) i : 10 - 5 i

= 10 - 5 i

+ 5 a^{2} + 10 ab - 3 a - 6 b

72 - 18 + 8

\frac{3 x ^{2}}{x ^{4}}

- 4 \times 16

\frac{3}{x ^{2} - 25} \cdot \frac{10}{3 x - 15}