What is factor x^5-7x^4+9x^3+23x^2-50x+24 ?

The solution to factor x^5-7x^4+9x^3+23x^2-50x+24 is (x-1)^2(x+2)(x-3)(x-4)

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factor x^5-7x^4+9x^3+23x^2-50x+24

factor

x^{5} - 7 x^{4} + 9 x^{3} + 23 x^{2} - 50 x + 24

(x - 1)^{2} (x + 2) (x - 3) (x - 4)

Solution steps

x^{5} - 7 x^{4} + 9 x^{3} + 23 x^{2} - 50 x + 24

Use the rational root theorem

= (x - 1) \frac{x ^{5} - 7 x ^{4} + 9 x ^{3} + 23 x ^{2} - 50 x + 24}{x - 1}

\frac{x ^{5} - 7 x ^{4} + 9 x ^{3} + 23 x ^{2} - 50 x + 24}{x - 1} = x^{4} - 6 x^{3} + 3 x^{2} + 26 x - 24

= (x - 1) (x^{4} - 6 x^{3} + 3 x^{2} + 26 x - 24)

Factor

x^{4} - 6 x^{3} + 3 x^{2} + 26 x - 24 : (x - 1) (x + 2) (x - 3) (x - 4)

= (x - 1) (x - 1) (x + 2) (x - 3) (x - 4)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x - 1)^{2} (x + 2) (x - 3) (x - 4)

\frac{2 π}{3.6}

1690 \cdot ⎩ ⎨ ⎧ \frac{[ ( 1 + 0.07 ) ^{38} - 1 ]}{0.07} ⎭ ⎬ ⎫

(x + 1) (x + 2) = 0

\frac{x + 5}{5} - \frac{x + 5}{24} = \frac{x + 6}{10} + \frac{x + 4}{60}

1 + 2 u < - 3

What is factor x^5-7x^4+9x^3+23x^2-50x+24 ?
The solution to factor x^5-7x^4+9x^3+23x^2-50x+24 is (x-1)^2(x+2)(x-3)(x-4)