What are the solutions to the equation 3x^2-16x+6=0 ?

The solutions to the equation 3x^2-16x+6=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3

Find the zeros of 3x^2-16x+6=0

The zeros of 3x^2-16x+6=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3

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3 x^{2} - 16 x + 6 = 0

x = \frac{8 + 46}{3}, x = \frac{8 - 46}{3}

Decimal Notation

x = 4.92744 \dots, x = 0.40589 \dots

Solution steps

3 x^{2} - 16 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 6 = 246

x_{1, 2} = \frac{- ( - 16 ) \pm 2 46}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 46}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 2 46}{2 \cdot 3}

x = \frac{- ( - 16 ) + 2 46}{2 \cdot 3} : \frac{8 + 46}{3}

x = \frac{- ( - 16 ) - 2 46}{2 \cdot 3} : \frac{8 - 46}{3}

The solutions to the quadratic equation are:

x = \frac{8 + 46}{3}, x = \frac{8 - 46}{3}

\frac{1}{2} - \frac{1}{8}

\frac{1}{x - 1} + \frac{2}{x} < 0

\frac{p + 1}{2} = \frac{3 p + 7}{5}

9 x^{2} - 18 x + 8 = 0

- 5 < 5 - 2 x \leq - 2

What are the solutions to the equation 3x^2-16x+6=0 ?
The solutions to the equation 3x^2-16x+6=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3
Find the zeros of 3x^2-16x+6=0
The zeros of 3x^2-16x+6=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3