What are the solutions to the equation 9x^2-18x+8=0 ?

The solutions to the equation 9x^2-18x+8=0 are x= 4/3 ,x= 2/3

Find the zeros of 9x^2-18x+8=0

The zeros of 9x^2-18x+8=0 are x= 4/3 ,x= 2/3

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9 x^{2} - 18 x + 8 = 0

x = \frac{4}{3}, x = \frac{2}{3}

Decimal Notation

x = 1.33333 \dots, x = 0.66666 \dots

Solution steps

9 x^{2} - 18 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 8}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 8 = 6

x_{1, 2} = \frac{- ( - 18 ) \pm 6}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 6}{2 \cdot 9}

x = \frac{- ( - 18 ) + 6}{2 \cdot 9} : \frac{4}{3}

x = \frac{- ( - 18 ) - 6}{2 \cdot 9} : \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = \frac{2}{3}

- 5 < 5 - 2 x \leq - 2

3 x - 5 + 4 = 11

10 b + 7 < 5 b + 8

(2 x^{3} + 3 x^{4})^{2}

\frac{1}{9} + \frac{2}{9}

What are the solutions to the equation 9x^2-18x+8=0 ?
The solutions to the equation 9x^2-18x+8=0 are x= 4/3 ,x= 2/3
Find the zeros of 9x^2-18x+8=0
The zeros of 9x^2-18x+8=0 are x= 4/3 ,x= 2/3