What is factor 6n^3+3n^2+8n+4 ?

The solution to factor 6n^3+3n^2+8n+4 is (2n+1)(3n^2+4)

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factor 6n^3+3n^2+8n+4

factor

6 n^{3} + 3 n^{2} + 8 n + 4

(2 n + 1) (3 n^{2} + 4)

Solution steps

6 n^{3} + 3 n^{2} + 8 n + 4

= (6 n^{3} + 3 n^{2}) + (8 n + 4)

Factor out

3 n^{2}

from

6 n^{3} + 3 n^{2} : 3 n^{2} (2 n + 1)

Factor out

4

from

8 n + 4 : 4 (2 n + 1)

= 3 n^{2} (2 n + 1) + 4 (2 n + 1)

Factor out common term

2 n + 1

= (2 n + 1) (3 n^{2} + 4)

\frac{4 + 7 i}{2 + 5 i}

\frac{1}{tan ( x ) + cot ( x )}

- 6 x^{2} - 6 x + 12

(1 - x^{2})^{2}

(u^{2} - 1)^{3}

What is factor 6n^3+3n^2+8n+4 ?
The solution to factor 6n^3+3n^2+8n+4 is (2n+1)(3n^2+4)