What is the d/(dp)(e^{-ipi}) ?

The d/(dp)(e^{-ipi}) is e^{-ipi}*1

What is the first d/(dp)(e^{-ipi}) ?

The first d/(dp)(e^{-ipi}) is e^{-ipi}*1

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\frac{d}{d p} (e^{- i p i})

e^{- i p i} \cdot 1

Solution steps

\frac{d}{d p} (e^{- i p i})

Apply the chain rule:

e^{- i p i} \frac{d}{d p} (- i p i)

= e^{- i p i} \frac{d}{d p} (- i p i)

\frac{d}{d p} (- i p i) = 1

= e^{- i p i} \cdot 1

- \frac{5}{8} (3 p + 8)

y + y + y + y

(- 4 x^{- 2}) (9 x^{9})

2 i + 2 i

\frac{x ^{- 4}}{x ^{- 7}}