7(3-x)>= 5

Solution

7 (3 - x) \geq 5

x \leq \frac{16}{7}

Interval Notation

(- \infty, \frac{16}{7}]

Decimal Notation

x \leq 2.28571 \dots

Solution steps

7 (3 - x) \geq 5

Divide both sides by

7

3 - x \geq \frac{5}{7}

Move

3

to the right side

- x \geq - \frac{16}{7}

Multiply both sides by

- 1

x \leq \frac{16}{7}

(16 x^{2} y^{4}) (\frac{1}{4} x^{5} y)

x = 4000 (1 + 0.7)^{2}

\frac{16 x ^{2} y}{24 x y ^{3}}

\frac{5 x - 4}{6} \geq \frac{5}{12}

\frac{x ^{- 2}}{x ^{- 2} - y ^{- 2}}