What are the solutions to the equation 6x^2+42x+36=0 ?

The solutions to the equation 6x^2+42x+36=0 are x=-1,x=-6

Find the zeros of 6x^2+42x+36=0

The zeros of 6x^2+42x+36=0 are x=-1,x=-6

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6 x^{2} + 42 x + 36 = 0

x = - 1, x = - 6

Solution steps

6 x^{2} + 42 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 6 \cdot 36}{2 \cdot 6}

4 2^{2} - 4 \cdot 6 \cdot 36 = 30

x_{1, 2} = \frac{- 42 \pm 30}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 42 + 30}{2 \cdot 6}, x_{2} = \frac{- 42 - 30}{2 \cdot 6}

x = \frac{- 42 + 30}{2 \cdot 6} : - 1

x = \frac{- 42 - 30}{2 \cdot 6} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

x - 7 = 13

\frac{9 ^{- 2}}{9 ^{- 6}}

\frac{3 x}{x - 1} \leq \frac{x}{x + 4} + 3

x^{2} + 7 x y - 18 y^{2}

5^{6}

What are the solutions to the equation 6x^2+42x+36=0 ?
The solutions to the equation 6x^2+42x+36=0 are x=-1,x=-6
Find the zeros of 6x^2+42x+36=0
The zeros of 6x^2+42x+36=0 are x=-1,x=-6