What is 4/(x^2+x)-3/(x^2-1) ?

The solution to 4/(x^2+x)-3/(x^2-1) is (x-4)/(x(x+1)(x-1))

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simplify 4/(x^2+x)-3/(x^2-1)

simplify

\frac{4}{x ^{2} + x} - \frac{3}{x ^{2} - 1}

\frac{x - 4}{x ( x + 1 ) ( x - 1 )}

Solution steps

\frac{4}{x ^{2} + x} - \frac{3}{x ^{2} - 1}

Least Common Multiplier of

x^{2} + x, x^{2} - 1 : x (x + 1) (x - 1)

Adjust Fractions based on the LCM

= \frac{4 ( x - 1 )}{x ( x + 1 ) ( x - 1 )} - \frac{3 x}{x ( x + 1 ) ( x - 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{4 ( x - 1 ) - 3 x}{x ( x + 1 ) ( x - 1 )}

Simplify

4 (x - 1) - 3 x : x - 4

= \frac{x - 4}{x ( x + 1 ) ( x - 1 )}

\frac{1}{4} 6 - \frac{1}{4} 2

(\frac{1}{2} x^{3})^{2}

\frac{1}{20} + \frac{1}{10}

\frac{x}{2 x - 1} + \frac{x + 1}{x - 2}

- 354 + 26

What is 4/(x^2+x)-3/(x^2-1) ?
The solution to 4/(x^2+x)-3/(x^2-1) is (x-4)/(x(x+1)(x-1))