What is 2/(x+3)+7/(x^2-9) ?

The solution to 2/(x+3)+7/(x^2-9) is (2x+1)/((x+3)(x-3))

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simplify 2/(x+3)+7/(x^2-9)

simplify

\frac{2}{x + 3} + \frac{7}{x ^{2} - 9}

\frac{2 x + 1}{( x + 3 ) ( x - 3 )}

Solution steps

\frac{2}{x + 3} + \frac{7}{x ^{2} - 9}

Least Common Multiplier of

x + 3, x^{2} - 9 : (x + 3) (x - 3)

Adjust Fractions based on the LCM

= \frac{2 ( x - 3 )}{( x + 3 ) ( x - 3 )} + \frac{7}{( x + 3 ) ( x - 3 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{2 ( x - 3 ) + 7}{( x + 3 ) ( x - 3 )}

Simplify

2 (x - 3) + 7 : 2 x + 1

= \frac{2 x + 1}{( x + 3 ) ( x - 3 )}

\frac{4}{5} \times \frac{9}{10}

- x^{2} \times (- x^{2})

sin (x) sin (x)

2^{l o g_{2} (16)}

\frac{6}{8} \div \frac{2}{8}

What is 2/(x+3)+7/(x^2-9) ?
The solution to 2/(x+3)+7/(x^2-9) is (2x+1)/((x+3)(x-3))