What is (x^2+3x)/(x^2+6x+9) ?

The solution to (x^2+3x)/(x^2+6x+9) is x/(x+3)

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simplify (x^2+3x)/(x^2+6x+9)

simplify

\frac{x ^{2} + 3 x}{x ^{2} + 6 x + 9}

\frac{x}{x + 3}

Solution steps

\frac{x ^{2} + 3 x}{x ^{2} + 6 x + 9}

Factor

x^{2} + 3 x : x (x + 3)

= \frac{x ( x + 3 )}{x ^{2} + 6 x + 9}

Factor

x^{2} + 6 x + 9 : (x + 3)^{2}

= \frac{x ( x + 3 )}{( x + 3 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 3)^{2} = (x + 3) (x + 3)

= \frac{x ( x + 3 )}{( x + 3 ) ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{x}{x + 3}

3 i (8 - 9 i)

\frac{32}{18}

2 0^{2} - 1 6^{2}

\frac{1}{7} \times 3

(x - x^{3})^{2}