What is (4x^2-7x-2)/(8x^3+2x^2+4x+1) ?

The solution to (4x^2-7x-2)/(8x^3+2x^2+4x+1) is (x-2)/(2x^2+1)

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simplify (4x^2-7x-2)/(8x^3+2x^2+4x+1)

simplify

\frac{4 x ^{2} - 7 x - 2}{8 x ^{3} + 2 x ^{2} + 4 x + 1}

\frac{x - 2}{2 x ^{2} + 1}

Solution steps

\frac{4 x ^{2} - 7 x - 2}{8 x ^{3} + 2 x ^{2} + 4 x + 1}

Factor

4 x^{2} - 7 x - 2 : (4 x + 1) (x - 2)

= \frac{( 4 x + 1 ) ( x - 2 )}{8 x ^{3} + 2 x ^{2} + 4 x + 1}

Factor

8 x^{3} + 2 x^{2} + 4 x + 1 : (4 x + 1) (2 x^{2} + 1)

= \frac{( 4 x + 1 ) ( x - 2 )}{( 4 x + 1 ) ( 2 x ^{2} + 1 )}

Cancel the common factor:

4 x + 1

= \frac{x - 2}{2 x ^{2} + 1}

- 675

3 x^{2} + 12 x - 96

(32 uv)^{\frac{2}{5}}

x^{2} + 13 x + 30

x^{2} + 13 x + 36

What is (4x^2-7x-2)/(8x^3+2x^2+4x+1) ?
The solution to (4x^2-7x-2)/(8x^3+2x^2+4x+1) is (x-2)/(2x^2+1)