What is factor 5u^4-40u^3+35u^2 ?

The solution to factor 5u^4-40u^3+35u^2 is 5u^2(u-1)(u-7)

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factor 5u^4-40u^3+35u^2

factor

5 u^{4} - 40 u^{3} + 35 u^{2}

5 u^{2} (u - 1) (u - 7)

Solution steps

5 u^{4} - 40 u^{3} + 35 u^{2}

Factor out common term

5 u^{2} : 5 u^{2} (u^{2} - 8 u + 7)

= 5 u^{2} (u^{2} - 8 u + 7)

Factor

u^{2} - 8 u + 7 : (u - 1) (u - 7)

= 5 u^{2} (u - 1) (u - 7)

2 x^{3} + 3 x^{2} - 8 x - 12

\frac{x - 2}{x ^{2} - 36} \geq 0

\frac{20 x ^{2} y ^{2}}{4 x y}

\frac{1}{x + 1} + \frac{1}{x - 2} < 1

12 x + 7 < - 11 and 5 x - 8 \geq 40

What is factor 5u^4-40u^3+35u^2 ?
The solution to factor 5u^4-40u^3+35u^2 is 5u^2(u-1)(u-7)