What is (2x^2-2y^2)/(x+y) ?

The solution to (2x^2-2y^2)/(x+y) is 2x-2y

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simplify (2x^2-2y^2)/(x+y)

simplify

\frac{2 x ^{2} - 2 y ^{2}}{x + y}

2 x - 2 y

Solution steps

\frac{2 x ^{2} - 2 y ^{2}}{x + y}

Factor out common term

2

= \frac{2 ( x ^{2} - y ^{2} )}{x + y}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

x^{2} - y^{2} = (x + y) (x - y)

= \frac{2 ( x + y ) ( x - y )}{x + y}

Cancel the common factor:

x + y

= 2 (x - y)

Apply the distributive law:

a (b - c) = ab - a c

2 (x - y) = 2 x - 2 y

= 2 x - 2 y

- 3 \cdot (- 7)

Γ (\frac{3}{4})

(L - x)^{4}

\frac{\frac{1}{6}}{\frac{1}{3}}

(a - 4)^{5}