What is (27x^3y^5)/(3x^4y^2) ?

The solution to (27x^3y^5)/(3x^4y^2) is (9y^3)/x

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simplify (27x^3y^5)/(3x^4y^2)

simplify

\frac{27 x ^{3} y ^{5}}{3 x ^{4} y ^{2}}

\frac{9 y ^{3}}{x}

Solution steps

\frac{27 x ^{3} y ^{5}}{3 x ^{4} y ^{2}}

Factor the number:

27 = 3 \cdot 9

= \frac{3 \cdot 9 x ^{3} y ^{5}}{3 x ^{4} y ^{2}}

Cancel the common factor:

3

= \frac{9 x ^{3} y ^{5}}{x ^{4} y ^{2}}

Simplify

\frac{y ^{5}}{y ^{2}} : y^{3}

= \frac{9 x ^{3} y ^{3}}{x ^{4}}

Simplify

\frac{x ^{3}}{x ^{4}} : \frac{1}{x}

= \frac{9 y ^{3}}{x}

\frac{2}{2} 0.25

1 - 125 w^{3}

\frac{78}{13}

42 \cdot + 22

(x + 1) (3 x^{2} + 10 x - 6)