What are the solutions to the equation x^2+18x=-31 ?

The solutions to the equation x^2+18x=-31 are x=-9+5sqrt(2),x=-9-5sqrt(2)

Find the zeros of x^2+18x=-31

The zeros of x^2+18x=-31 are x=-9+5sqrt(2),x=-9-5sqrt(2)

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x^{2} + 18 x = - 31

x = - 9 + 52, x = - 9 - 52

Decimal Notation

x = - 1.92893 \dots, x = - 16.07106 \dots

Solution steps

x^{2} + 18 x = - 31

Move

31

to the left side

x^{2} + 18 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 31 = 102

x_{1, 2} = \frac{- 18 \pm 10 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 10 2}{2 \cdot 1}, x_{2} = \frac{- 18 - 10 2}{2 \cdot 1}

x = \frac{- 18 + 10 2}{2 \cdot 1} : - 9 + 52

x = \frac{- 18 - 10 2}{2 \cdot 1} : - 9 - 52

The solutions to the quadratic equation are:

x = - 9 + 52, x = - 9 - 52

\frac{1}{10} + \frac{1}{10}

15 \cdot 2

\frac{1}{2} x^{2} + \frac{1}{14} x - 1 = 0

6 m - 6 (- 7 - 4 m) = 192

d - 6 > - 4

What are the solutions to the equation x^2+18x=-31 ?
The solutions to the equation x^2+18x=-31 are x=-9+5sqrt(2),x=-9-5sqrt(2)
Find the zeros of x^2+18x=-31
The zeros of x^2+18x=-31 are x=-9+5sqrt(2),x=-9-5sqrt(2)