What is (x^2-5x+4)/(x^2-8x+7) ?

The solution to (x^2-5x+4)/(x^2-8x+7) is (x-4)/(x-7)

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simplify (x^2-5x+4)/(x^2-8x+7)

simplify

\frac{x ^{2} - 5 x + 4}{x ^{2} - 8 x + 7}

\frac{x - 4}{x - 7}

Solution steps

\frac{x ^{2} - 5 x + 4}{x ^{2} - 8 x + 7}

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{x ^{2} - 8 x + 7}

Factor

x^{2} - 8 x + 7 : (x - 1) (x - 7)

= \frac{( x - 1 ) ( x - 4 )}{( x - 1 ) ( x - 7 )}

Cancel the common factor:

x - 1

= \frac{x - 4}{x - 7}

1 \frac{1}{2} \times 3

- 6 + i^{4}

\frac{1}{3} \times \frac{4}{3}

\frac{1}{4} + \frac{3}{2} \times \frac{2}{3}

What is (x^2-5x+4)/(x^2-8x+7) ?
The solution to (x^2-5x+4)/(x^2-8x+7) is (x-4)/(x-7)