What are the solutions to the equation x^2+14x+98=0 ?

The solutions to the equation x^2+14x+98=0 are x=-7+7i,x=-7-7i

Find the zeros of x^2+14x+98=0

The zeros of x^2+14x+98=0 are x=-7+7i,x=-7-7i

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x^{2} + 14 x + 98 = 0

x = - 7 + 7 i, x = - 7 - 7 i

Solution steps

x^{2} + 14 x + 98 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 98}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot 98 : 14 i

x_{1, 2} = \frac{- 14 \pm 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 14 i}{2 \cdot 1}, x_{2} = \frac{- 14 - 14 i}{2 \cdot 1}

x = \frac{- 14 + 14 i}{2 \cdot 1} : - 7 + 7 i

x = \frac{- 14 - 14 i}{2 \cdot 1} : - 7 - 7 i

The solutions to the quadratic equation are:

x = - 7 + 7 i, x = - 7 - 7 i

\frac{1}{2} \cdot \frac{1}{5}

3 + \frac{x - 2}{x - 3} \leq 4

- x^{2} + 4 x + 12 = 0

3 p - 1 = 5 (p - 1) - 2 (7 - 2 p)

\frac{( 3 m ^{- 1} n ^{2} ) ^{4}}{( 2 m ^{- 2} n ) ^{3}}

What are the solutions to the equation x^2+14x+98=0 ?
The solutions to the equation x^2+14x+98=0 are x=-7+7i,x=-7-7i
Find the zeros of x^2+14x+98=0
The zeros of x^2+14x+98=0 are x=-7+7i,x=-7-7i