What is (x^8y^{-9})/(x^{-2)y^4} ?

The solution to (x^8y^{-9})/(x^{-2)y^4} is (x^{10})/(y^{13)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x^8y^{-9})/(x^{-2)y^4}

simplify

\frac{x ^{8} y ^{- 9}}{x ^{- 2} y ^{4}}

\frac{x ^{10}}{y ^{13}}

Solution steps

\frac{x ^{8} y ^{- 9}}{x ^{- 2} y ^{4}}

Simplify

\frac{x ^{8}}{x ^{- 2}} : x^{10}

= \frac{x ^{10} y ^{- 9}}{y ^{4}}

Simplify

\frac{y ^{- 9}}{y ^{4}} : \frac{1}{y ^{13}}

= \frac{x ^{10}}{y ^{13}}

\frac{x}{7} + \frac{7}{x}

i^{- 43}

x^{2} + 4 x - 60

sin (c) (x)

i^{42}

What is (x^8y^{-9})/(x^{-2)y^4} ?
The solution to (x^8y^{-9})/(x^{-2)y^4} is (x^{10})/(y^{13)}