What are the solutions to the equation 7x^2+7x+3=0 ?

The solutions to the equation 7x^2+7x+3=0 are x=-1/2+i(sqrt(35))/(14),x=-1/2-i(sqrt(35))/(14)

Find the zeros of 7x^2+7x+3=0

The zeros of 7x^2+7x+3=0 are x=-1/2+i(sqrt(35))/(14),x=-1/2-i(sqrt(35))/(14)

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7 x^{2} + 7 x + 3 = 0

x = - \frac{1}{2} + i \frac{35}{14}, x = - \frac{1}{2} - i \frac{35}{14}

Solution steps

7 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 7 \cdot 3}{2 \cdot 7}

Simplify

7^{2} - 4 \cdot 7 \cdot 3 : 35 i

x_{1, 2} = \frac{- 7 \pm 35 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 7 + 35 i}{2 \cdot 7}, x_{2} = \frac{- 7 - 35 i}{2 \cdot 7}

x = \frac{- 7 + 35 i}{2 \cdot 7} : - \frac{1}{2} + i \frac{35}{14}

x = \frac{- 7 - 35 i}{2 \cdot 7} : - \frac{1}{2} - i \frac{35}{14}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{35}{14}, x = - \frac{1}{2} - i \frac{35}{14}

∣ 2 x - 1 ∣ \leq 3

- 5 ∣ 1 - x ∣ - 4 < - 74

x^{2} + 3 x = 1

5 (8) - 2 y = 30

17 a x - 17 m x + 2 a y - 2 m y + 9 a z - 9 m z

What are the solutions to the equation 7x^2+7x+3=0 ?
The solutions to the equation 7x^2+7x+3=0 are x=-1/2+i(sqrt(35))/(14),x=-1/2-i(sqrt(35))/(14)
Find the zeros of 7x^2+7x+3=0
The zeros of 7x^2+7x+3=0 are x=-1/2+i(sqrt(35))/(14),x=-1/2-i(sqrt(35))/(14)