What is factor-8+j^{15} ?

The solution to factor-8+j^{15} is (j^5-2)(j^{10}+2j^5+4)

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factor-8+j^{15}

factor

- 8 + j^{15}

(j^{5} - 2) (j^{10} + 2 j^{5} + 4)

Solution steps

- 8 + j^{15}

Write in the standard form

= j^{15} - 8

Apply exponent rules

= (j^{5})^{3} - 2^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(j^{5})^{3} - 2^{3} = (j^{5} - 2) (j^{10} + 2 j^{5} + 2^{2})

= (j^{5} - 2) (j^{10} + 2 j^{5} + 2^{2})

2^{2} = 4

= (j^{5} - 2) (j^{10} + 2 j^{5} + 4)

3 x^{2} - 39 x + 36

\frac{x ^{3}}{3} - \frac{- 27 x ^{3}}{3}

\frac{27}{5}

\frac{( 3 x ^{- 4} ) ^{6}}{9 x ^{12}}

2 x^{2} + 14 x + 10

What is factor-8+j^{15} ?
The solution to factor-8+j^{15} is (j^5-2)(j^{10}+2j^5+4)