What is rationalize 1/(sqrt(7)-\sqrt{3)} ?

The solution to rationalize 1/(sqrt(7)-\sqrt{3)} is (sqrt(7)+sqrt(3))/4

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rationalize 1/(sqrt(7)-\sqrt{3)}

rationalize

\frac{1}{7 - 3}

\frac{7 + 3}{4}

Decimal Notation

1.09445 \dots

Solution steps

\frac{1}{7 - 3}

Multiply by the conjugate

\frac{7 + 3}{7 + 3}

= \frac{1 \cdot ( 7 + 3 )}{( 7 - 3 ) ( 7 + 3 )}

1 \cdot (7 + 3) = 7 + 3

(7 - 3) (7 + 3) = 4

= \frac{7 + 3}{4}

\frac{- 3}{2} \times \frac{- 3}{2}

8 a^{3} + b^{3}

a^{\frac{1}{2}} a^{\frac{1}{6}}

(x^{\frac{5}{4}})^{2}

- 2 (- 2 x)

What is rationalize 1/(sqrt(7)-\sqrt{3)} ?
The solution to rationalize 1/(sqrt(7)-\sqrt{3)} is (sqrt(7)+sqrt(3))/4