What is (-3+i)/(i-1) ?

The solution to (-3+i)/(i-1) is 2+i

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simplify (-3+i)/(i-1)

simplify

\frac{- 3 + i}{i - 1}

2 + i

Solution steps

\frac{- 3 + i}{i - 1}

Rewrite

i - 1

in standard complex form:

- 1 + i

= \frac{- 3 + i}{- 1 + i}

Multiply by the conjugate

\frac{- 1 - i}{- 1 - i}

= \frac{( - 3 + i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )}

Simplify

\frac{( - 3 + i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )} : \frac{4 + 2 i}{2}

= \frac{4 + 2 i}{2}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{4}{2} + \frac{2}{2} i

Simplify

\frac{4}{2} + \frac{2}{2} i : 2 + i

= 2 + i

lo g_{2} (10000000)

lo g_{100} (10)

\frac{12.5}{16}

\frac{5}{3} \times 9

\frac{14 x ^{8} y ^{6}}{21 x ^{8} y ^{2}}