What is (\frac{2x+1)/(2x-1)}{(x^2)/(4x-2)} ?

The solution to (\frac{2x+1)/(2x-1)}{(x^2)/(4x-2)} is (2(2x+1))/(x^2)

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simplify (\frac{2x+1)/(2x-1)}{(x^2)/(4x-2)}

simplify

\frac{\frac{2 x + 1}{2 x - 1}}{\frac{x ^{2}}{4 x - 2}}

\frac{2 ( 2 x + 1 )}{x ^{2}}

Solution steps

\frac{\frac{2 x + 1}{2 x - 1}}{\frac{x ^{2}}{4 x - 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 2 x + 1 ) ( 4 x - 2 )}{( 2 x - 1 ) x ^{2}}

Cancel

\frac{( 2 x + 1 ) ( 4 x - 2 )}{( 2 x - 1 ) x ^{2}} : \frac{( 2 x + 1 ) \cdot 2}{x ^{2}}

= \frac{( 2 x + 1 ) \cdot 2}{x ^{2}}

= \frac{2 ( 2 x + 1 )}{x ^{2}}

2 \times + 4

\frac{11}{11}

2^{- 2 + 1}

\frac{2}{1000}

\frac{31}{21} - \frac{3}{14}

What is (\frac{2x+1)/(2x-1)}{(x^2)/(4x-2)} ?
The solution to (\frac{2x+1)/(2x-1)}{(x^2)/(4x-2)} is (2(2x+1))/(x^2)