What is x^3+5x^2>= 4x+20 ?

The solution to x^3+5x^2>= 4x+20 is -5 = 2

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x^3+5x^2>= 4x+20

x^{3} + 5 x^{2} \geq 4 x + 20

- 5 \leq x \leq - 2 or x \geq 2

Interval Notation

[- 5, - 2] \cup [2, \infty)

Solution steps

x^{3} + 5 x^{2} \geq 4 x + 20

Rewrite in standard form

x^{3} + 5 x^{2} - 20 - 4 x \geq 0

Factor

x^{3} + 5 x^{2} - 20 - 4 x : (x + 5) (x + 2) (x - 2)

(x + 5) (x + 2) (x - 2) \geq 0

Identify the intervals

- 5 \leq x \leq - 2 or x \geq 2

32 m^{2} n - 40 m n^{2}

x^{2} + ∣ x ∣ - 12 < x - 2

4 (2 y + 5) = 3 (5 y - 2)

\frac{6 y ^{3}}{4 y} \cdot \frac{16}{2 x ^{2}}

0. 5^{- 1}

What is x^3+5x^2>= 4x+20 ?
The solution to x^3+5x^2>= 4x+20 is -5<= x<=-2\lor x>= 2