What is factor 6x^3+7x^2-x-2 ?

The solution to factor 6x^3+7x^2-x-2 is (x+1)(2x-1)(3x+2)

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factor 6x^3+7x^2-x-2

factor

6 x^{3} + 7 x^{2} - x - 2

(x + 1) (2 x - 1) (3 x + 2)

Solution steps

6 x^{3} + 7 x^{2} - x - 2

Use the rational root theorem

= (x + 1) \frac{6 x ^{3} + 7 x ^{2} - x - 2}{x + 1}

\frac{6 x ^{3} + 7 x ^{2} - x - 2}{x + 1} = 6 x^{2} + x - 2

= (x + 1) (6 x^{2} + x - 2)

Factor

6 x^{2} + x - 2 : (2 x - 1) (3 x + 2)

= (x + 1) (2 x - 1) (3 x + 2)

\frac{6}{5 x} + \frac{7}{3 y}

6 \times (- 8)

10 \frac{1}{2} \div 1 \frac{3}{4}

6 \times 19

6 \times 35

What is factor 6x^3+7x^2-x-2 ?
The solution to factor 6x^3+7x^2-x-2 is (x+1)(2x-1)(3x+2)