What is cos(2x)\times 2+4sin^2(x)-2 ?

The solution to cos(2x)\times 2+4sin^2(x)-2 is 0

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simplify cos(2x)\times 2+4sin^2(x)-2

simplify

cos (2 x) \cdot 2 + 4 sin^{2} (x) - 2

0

Solution steps

cos (2 x) \cdot 2 + 4 sin^{2} (x) - 2

Use the Double Angle identity:

1 - 2 sin^{2} (x) = cos (2 x)

- 1 + 2 sin^{2} (x) = - cos (2 x)

= 2 (cos (2 x) - cos (2 x))

Factor

cos (2 x) 2 + 4 sin^{2} (x) - 2 : 2 (cos (2 x) + 2 sin^{2} (x) - 1)

= 2 (2 sin^{2} (x) + cos (2 x) - 1)

= 0

\frac{1}{\frac{3}{x ^{2} - 4} - 3}

tan^{2} (x) - tan (x)

\frac{12}{5} + 1

2 x - x^{2} - 1

224 - 554 + 12600

What is cos(2x)\times 2+4sin^2(x)-2 ?
The solution to cos(2x)\times 2+4sin^2(x)-2 is 0