What is factor+4x^5-x^3+32x^2-8 ?

The solution to factor+4x^5-x^3+32x^2-8 is (2x+1)(2x-1)(x+2)(x^2-2x+4)

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factor+4x^5-x^3+32x^2-8

factor

+ 4 x^{5} - x^{3} + 32 x^{2} - 8

(2 x + 1) (2 x - 1) (x + 2) (x^{2} - 2 x + 4)

Solution steps

4 x^{5} - x^{3} + 32 x^{2} - 8

= (4 x^{5} - x^{3}) + (32 x^{2} - 8)

Factor out

x^{3}

from

4 x^{5} - x^{3} : x^{3} (4 x^{2} - 1)

Factor out

8

from

32 x^{2} - 8 : 8 (4 x^{2} - 1)

= x^{3} (4 x^{2} - 1) + 8 (4 x^{2} - 1)

Factor out common term

4 x^{2} - 1

= (4 x^{2} - 1) (x^{3} + 8)

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= (2 x + 1) (2 x - 1) (x^{3} + 8)

Factor

x^{3} + 8 : (x + 2) (x^{2} - 2 x + 2^{2})

= (2 x + 1) (2 x - 1) (x + 2) (x^{2} - 2 x + 2^{2})

2^{2} = 4

= (2 x + 1) (2 x - 1) (x + 2) (x^{2} - 2 x + 4)

36 - 16

- (x + 5)

3 \times \frac{3}{2}

\frac{5}{6} \div \frac{3}{5}

64 d^{5} - 24 d^{2}

What is factor+4x^5-x^3+32x^2-8 ?
The solution to factor+4x^5-x^3+32x^2-8 is (2x+1)(2x-1)(x+2)(x^2-2x+4)