What is factor b^2-4b+3 ?

The solution to factor b^2-4b+3 is (b-1)(b-3)

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factor b^2-4b+3

factor

b^{2} - 4 b + 3

(b - 1) (b - 3)

Solution steps

b^{2} - 4 b + 3

Break the expression into groups

= (b^{2} - b) + (- 3 b + 3)

Factor out

b

from

b^{2} - b : b (b - 1)

Factor out

- 3

from

- 3 b + 3 : - 3 (b - 1)

= b (b - 1) - 3 (b - 1)

Factor out common term

b - 1

= (b - 1) (b - 3)

\frac{3}{4} - \frac{1}{2}

\frac{x - 4}{2 x} + \frac{2 x + 3}{2 x - 3}

3 \times \frac{2}{4}

- 108 \div 12

8 x^{2} - 6 x - 27