What is (8-14i)/(1-3i) ?

The solution to (8-14i)/(1-3i) is 5+i

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simplify (8-14i)/(1-3i)

simplify

\frac{8 - 14 i}{1 - 3 i}

5 + i

Solution steps

\frac{8 - 14 i}{1 - 3 i}

Multiply by the conjugate

\frac{1 + 3 i}{1 + 3 i}

= \frac{( 8 - 14 i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )}

Simplify

\frac{( 8 - 14 i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )} : \frac{50 + 10 i}{10}

= \frac{50 + 10 i}{10}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{50}{10} + \frac{10}{10} i

Simplify

\frac{50}{10} + \frac{10}{10} i : 5 + i

= 5 + i

lo g_{e} (x^{2})

12 x^{2} + 12 x - 3

(9 - i) + (- 6 + 7 i)

\frac{8 x ^{3} + 8 x ^{2} + 12 x + 5}{2 x + 1}

(3 y - 3)^{4}