What is x^2+(x+1)^2+(x+2)^2 ?

The solution to x^2+(x+1)^2+(x+2)^2 is 3x^2+6x+5

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simplify x^2+(x+1)^2+(x+2)^2

simplify

x^{2} + (x + 1)^{2} + (x + 2)^{2}

3 x^{2} + 6 x + 5

Solution steps

x^{2} + (x + 1)^{2} + (x + 2)^{2}

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= x^{2} + x^{2} + 2 x + 1 + (x + 2)^{2}

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

= x^{2} + x^{2} + 2 x + 1 + x^{2} + 4 x + 4

Group like terms

= x^{2} + x^{2} + x^{2} + 2 x + 4 x + 1 + 4

Add similar elements:

x^{2} + x^{2} + x^{2} = 3 x^{2}

= 3 x^{2} + 2 x + 4 x + 1 + 4

Add similar elements:

2 x + 4 x = 6 x

= 3 x^{2} + 6 x + 1 + 4

Add the numbers:

1 + 4 = 5

= 3 x^{2} + 6 x + 5

43

62

\frac{1}{4} \times 0

24336

\frac{π}{\frac{2}{π ^{2}}}